Creeperhissboom

The arc length of QR is 120/360 of 16pi, which is the circumference. That is 16pi/3

The central angle in radians is 2/3pi. 180 degrees in radiansis pi and 360 is 2pi.

The area of the sector is 64pi/3. Like 71, we just set up a proportion again. it is just a third of the total area

The equation is (x-3)^2+(y+4)^2=4

Because the basic form is (x-h)^2+(y-k)^2=r^2 and (h,k) is the center and r is the radius.

We can do the last one by completing the square.

We take the square of half of the coefficients.

(x-3)^2+(y+2)^2=-10

Sorry if these were not detailed, I didn't have a calculator and was in a hurry.

Oh okay

I got it like 10 minutes after i asked for help. Thanks anyways! 

THANKS CPHILL :DDDD

Hey there,

Try substituting 24n+51 into m for 2m

Then, use the Euclidean Algorithm and repeatedly subtract 3n from 2(24n+51)

Or check the NT message board. I had the same problem :)

And, additionally, I have to say that you left out the x next to the first 5 in the ceiling. I still don't know if it is infinity or just 6..

@CPhill, call me CHB from now on. It must hurt fingers to type it all out :D

There was no picture. It is a regular tetrahedron, so any orientation will be fine.

Yes, because 1/8 and 8 are both rational. Therefore it is B since that would add up to 65/8 or 8 1/8

Actually, I think that it is n/2 = 20?

Thanks, Cphill for the help though, I couldn't figure M at first.

That isn't right, sorry. 5 and 1 dont multiply to 10