Because AB and CD are parallel, 40 degrees.
Because BC and AD are parallel, 59 degrees.
Finally, z = 180 - x - y = 180 - 40 - 59 = 81 degrees.
The formula for circular acceleration is \(a = \frac{v^2}{r} = \frac{53 (\frac{m}{s})^2}{422 m} = 6.656 \frac{m}{s^2}\).
Therefore, the force is \(F = ma = (695 kg)(6.656 \frac{m}{s^2}) = \boxed{4625 N}\)
The shape is a parallelogram, as one set of sides is parallel and the other set of sides have the same length.
So, x = 180 - 48 = 134 degrees.
The rock hits the surface when the height is 0, or when \(-t^2 + 8t + 10 = 0\)
\(t^2 - 8t - 10 = 0 \)
Use the quadratic formula: t = -1.099 and 9.099. Time can't be negative, so the answer is t = 9.099.
Let the intersection of AC and BD be O.
z = 180 - 96 - 40 = 44 degrees.
Edit: It appears that most of my answer has been deleted, sorry about that.
Complete the square.
\(5x^2 - 20x + 1357 = 5(x-2)^2 + 1337\).
So, the minimum value is 1337.
\(\frac{7+x}{17+x} = \frac{3}{5}\)
\(5(7+x) = 3(17+x)\)
\(35 + 5x = 51 + 3x\)
\(2x = 16\)
\(\boxed{x=8}\)
The only way to put it in the calculator is to convert it entirely to inches.
5 ' 10'' = 5(12) + 10 = 70 inches.
Then you would put that in the calculator.
This is a repost: https://web2.0calc.com/questions/trapezoid_21
Hope this helps.
The value of f(2) is the y-coordinate of the point where x = 2. So, f(2) = 4.
