\(\frac{15}{3+2} - 8(3) + 7(5+3) = \frac{15}{5} - 24 + 7(12) = 3 - 24 + 84 = \boxed{63}\)
Let the sides be a, b, and c.
\(c^2 = a^2 + b^2 - 2ab \cos C.\)
You can replace c, a, and b interchangeably. This should help:
https://en.wikipedia.org/wiki/Law_of_cosines
-440 + 114 = -326
\(25 - x^2 \geq 0 \implies -5 \leq x \leq 5\)
\(-(x-2) \ge 0 \implies x \le 2\)
Put the two inequalities together: \(x \in [-5, 2]\). This is an interval of length 7.
\((508+ 1749i) + (-1322 +1949i) = \boxed{-814+3698i}\)
2 cos 2x= 1
cos 2x = 1/2
2x = pi/3, 2pi/3
x = pi/6, pi/3
(i / 2)^2 = (i^2) / (2^2) = -1/4
In that case, the "2" is called a subscript.
Tenths: GCF(16, 40) = 8
Hundredths: 8 - 3 = 5
Thousandths: 1
Tenthousandths: 9
Decimal: 0.8519
Thousandths: GCF(9, 18, 27) = 9, so it's 3
Hundredths: 3 - 2 = 1
Tenths: 9
Decimal: 0.913
