Let the length be L and the width be W. Then, \(\sqrt{L^2 + W^2} = 40\). No other information is given, so this is the best I can do.
Let the number you are trying to convert be x%.
\(x\% = \frac{x}{100}\)
Hope this helped.
This is a divisibility rule for 11. Here's more information about divisibility rules:
https://en.wikipedia.org/wiki/Divisibility_rule#:~:text=If%20the%20number%20of%20digits,must%20be%20divisible%20by%2011.&text=If%20the%20number%20of%20digits%20is%20odd%2C%20subtract%20the%20first,must%20be%20divisible%20by%2011.
This is binomial expansion.
\((x+2)^6 = {6 \choose 0}x^62^0 + {6 \choose 1}x^52^1 + {6 \choose 2}x^42^2 + {6 \choose 4}x^22^4 + {6 \choose 5}x^12^5 + {6 \choose 6}x^02^6\)
Miko and Freya saved the same amount of money, so let this amount be x.
5(x - 32) = x + 32
5x - 160 = x +32
4x = 192
x = 48
Freya had x + 32 = 80 dollars in the end.
\(\frac{\sqrt{2} \cdot \sqrt{3} \cdot \sqrt{4}}{\sqrt{5} \cdot \sqrt{7} \cdot \sqrt{9}}\)
\(\frac{2 \sqrt{6}}{3 \sqrt{35}} \cdot \frac{\sqrt{35}}{\sqrt{35}} = \frac{2\sqrt{210}}{105}\)
This is all for now, I'm going to bed.
\(\frac{1}{\frac{\sqrt{2}+2}{\sqrt{2}+1}} = \frac{\sqrt{2}+1}{\sqrt{2}+2} \cdot \frac{\sqrt{2}-2}{\sqrt{2}-2}\)
\(\frac{2 + \sqrt{2} - 2\sqrt{2} - 2}{-2}\)
\(\boxed{-\sqrt{2}/2}\)
\(\frac{16 \cdot 45}{7} = \boxed{\frac{720}{7}}\)
The table models the equation y = 26x for color printing.
The printer will print black and white pages at a faster rate.
\(\frac{1}{6} \div 3 = \boxed{\frac{1}{18}}\)