Total number of coin flip configurations: \(2^{10} = 1024\)
(2 choices for each flip: heads or tails, for 10 flips)
heads in 5 flips: \(10 \choose 5\)
(There are 10 choose 5 ways to rearrange the flips in the sequence HHHHHTTTTT.)
heads in 6 flips: \(10 \choose 6\)
heads in 7 flips: \(10 \choose 7\)
etc.
probability = \(\frac{{10 \choose 5} + {10 \choose 6} + {10 \choose 7} + {10 \choose 8} + {10 \choose 9} + {10 \choose 10}}{2^{10}} = \frac{628}{1024} = \boxed{\frac{157}{256}.} \)
.