CubeyThePenguin

The area covered is a sector of a circle with angle 90 degrees and radius 70.

\(A = \frac{90}{360} \pi (70)^2 = \frac{4900}{4} \pi \approx \boxed{3848}\) square feet

We can write every angle in terms of the second angle. Also, we know that the angles in a triangle must add to 180 degrees.

(2x - 15) + x + 33 = 180

3x + 18 = 180

3x = 162

x = 54

The three angles's measures are 93 degrees, 54 degrees, and 33 degrees, respectively. The largest angle's measure is 93 degrees.

yellow beans in the first bag = 26 * 50% = 13

yellow beans in the second bag = 28 * 25% = 7

yellow beans in the third bag = 30 * 50% = 15

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all yellow beans in all bags = 13 + 7 + 15 = 35

all beans in all bags = 26 + 28 + 30 = 84

percentage of yellow beans = (35/84) * 100% = 42%

Let Kendrick's age be x and his daughter's age be y. We can use the information in the problem to write a system of equations.

x = 3y + 1

x + 4 = 3(y + 4) - 7

x = 3y + 1

x = 3y + 1

This equation has infinite solutions, so any ordered pair (x, y) would solve this problem.

geometric sequence in general: a, ar, ar^2, ...

where a is the first term and r is the common ratio.

140 = a

560 = ar^2

Divide to get 4 = r^2, or r = 2. So, the second term is 140 * 2 = 280.

g(g(-1)) = g(3) = -6

First, we need to find the area of the trapezoid. (the average of the two bases multiplied by the height)

\(A = \frac{10 + 14}{2} \cdot 8 = 96\)

This area would take 96/6 = 16 minutes to wash.

Let the width be W, the length be L, and the height be H.

total length of all edges = 4(W + L + H) = 40 --> W + L + H = 10

total surface area = 2(WL + WH + LH) = 48 --> WL + WH + LH = 24

We want to find sqrt(W^2 + L^2 + H^2)

We can use the following algebraic identity:

(W + L + H)^2 = W^2 + L^2 + H^2 + 2WL + 2WH + LH

100 = W^2 + L^2 + H^2 + 2(24)

W^2 + L^2 + H^2 = 52

The space diagonal's length is therefore \(\boxed{\sqrt{52}}.\)

This question was answered already: https://web2.0calc.com/questions/solve-g-x-10-and-g-x-gt-f-x-for-the-given-equations#r1

Let A be the price of an adult ticket and C be the price of a child ticket.

4A + 3C = 156  (eq. 1)

3A + 4C = 145  (eq. 2)

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7A + 7C = 301

A + C = 43 (eq. 3)

Multiply eq. 3 by 4 and subtract from eq. 1.

4A + 4C = 172

4A + 3C = 156

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C = 16 ------> A = 43 - 16 = 27.