(Q-11)
This is a potential energy calculation. The energy is the same whether this is occurs in 4 seconds or 4 minutes. (Note: there is a difference in power because of this).
Here a mass is moved 0.8 meters vertically against a force of 9.81m/s2. Potential Energy = Mass x (Force of Gravity per Kg) x vertical distance 20Kg * (9.81m/s2) * 0.8M
$$E = m \times g \times h = 20 \textrm{ kg} \times 9.81 \frac{\textrm{N}}{\textrm{kg}} \times h$$
$$E = 20 \textrm{ kg} \times 9.81 \frac{\textrm{N}}{\textrm{kg}} \times 0.8m \ =\ 156.96J \\$$
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(Q-21)
The answer is A.
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(Q-22) Which shown arrows represents correctly the electric field at point p.
The answer is A. Electric fields are conventionally shown as moving to a negative charge.
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(Q-30)
Magnetic field = Permeability * Turn density * Current
Current = (Magnetic field) / (Permeability * Turn density)
The relative permeability here is assumed to be (1). (This is used as a multiplier of absolute permeability).
Turn density = The number of “loops” of wire uniformly distributed over a length of 1 meter.
110turns/0.5Meters = 220turns/meter
Magnetic field in milliTesla’s : 2.5mT = 0.002500 T
The magnetic field inside a solenoid is proportional to the applied current and the number of turns per unit length. The field inside is considered constant and independent of the diameter of the solenoid.
The magnetic field only depends on the current (I = amps), the number of turns per unit length (N/L), and the permeability of the core (mu0).
B= mu0(N/L) * I mu0 is Permeability in a vacuum (or air)
I=B/(mu0(N/L)
$$I = \frac{B}{mu_0 \frac {N}{L}}$$
$$I = \frac{B}{220 *\mu_0} \ = \ 9.04 A\\$$
Where
$$\\ \mu_0 = \ 4\pi \* 10^-7} \ H M^-^1$$
Yields Tesla measure of the ratio between enclosed magnetic field and the current.
0.002500 T corresponds to 9.04 Amps. (Answer D).
~~D~~