ElectricPavlov

Here is the graph:

It is 3/4 of the total perimeter   plus two radii       3/4  *   pi *  2 * 15      +  15    + 15  units

There may be an easier way to do this....but here is one way

Distance between   origin (0,0)    and    (x, x^2 -2)   using distance formula

    d = sqrt ( x-0)^2  + ( x^2 -2)^2 )

       = (x^4 -3x^2 +4)^1/2

Now take the derivative to find where the slope of this fxn = 0

     1/2 (4x^3 - 6x) / ( sqrt (x^4-3x^2+4)    = 0

          this = 0 when the numerator = 0       2x^3 - 3x   = 0

                                                                    x (2x^2 -3) = 0     means x = 0 or +- sqrt (3/2)

Plugging these values of x into the original equation    x^2 - 2     results in coordinate pairs  ( 0, -2)  and  ( sqrt (3/2) , -0.5)  )  (and - sqrt(3/2), - 0.5)

    Now, using these pairs and the origin in the distance formula shows the blue pair(s) result in the shortest distance to the origin

           sqrt ( sqrt(3/2)²  + (-.5)² ) = d = sqrt ( 7/4) = sqrt (7 ) /2 = 1.32287 units

(2007,1)    (223,3)

88 students - 14 students = 74 students have fangs fur or both

Using your given numbers ( which seem to be a bit 'off')      Furbearers = 59.2       fangs = 29.6       both = 14.8

Here is a Venn diagram:

Slope =   (y1-y2) / (x1-x2)  = -19/5

y = -19/5 x + b    sub in either point to find   b  =  - 36/5  

y = -19/5 x - 36/5          now multiply through by 5

5y + 19x = -36              now divide through by -36   to finish

    x / ( -19/36)    +   y / ( -36/5)    = 1  

LOL    'ellipse'      

Since it is already divisible by 5 , the smallest positive integer you could add to it would be '5' to still be divisible by 5 .

8t^2 <= -10t+3

8t^2  + 10 t   -3   <= 0            This is a bowl shaped parabola......the area in question will be between and include the zeroes

quadratic formula shows the zeroes (roots)         t = 1/4   and - 1.5  

-1.5 <= t <= .25  

2,16