The second one is the second choice
when j =
1 the value is -5
2 -1
3 3
4 7
5 11
I think the first one is the 4th choice
j =
1 1
2 1/4
3 1/16
4 1/64
5 1/256 (I think you typed the red terms incorrectly in your question.
\(\sum_{1}^{40}\) 7n-12
The area of the WHOLE figure is 1/2 b h = 1/2 ( 36)(24) = 432 cm^2
Now subtract the small right triangles in the corners
- 2 x 1/2 x 6 x FG
via similar triangles
CH/HB = FG/6
24/18 = FG/6
FG = 8
- 2 x 1/2 x 6 x 8 = -48
Pentagon area = 432 - 48 = 384 cm^2
The sin of a 90 degree angle is 1 .
Since it is an isoc right triangle angle ABC (and ACB) are each 45 degrees . Trisecting the 45 degree angle results in three 15 degree angles . Angle ABD includes two of these so it is 30 degrees.
The resulting triangle (ABD) is 30 degrees + 90 degrees + 60 degrees. BDEA = 60 degrees.
I THINK the second question is as follows
each switch controls one bank , so there is EIGHT ways to have ONE bank on
then for TWO banks there is 8 C 2 ways = 28 ways
28+8 = 36 ways to have either one bank or two banks on,
~EP
That may be true, but on the left you still have a LOG (negative number) .....So I am confused.
2 Log (a-2b) = log(a-2b)^2
seems invalid as the left side of the equation is invalid if (a-2b) is negative
Does anyone know for SURE?
Help !
Wondering if a/b =1 might be considered an extraneous (invalid) solution, as it would result in a
LOG (negative number) ??
You are correct......I had already looked it up. Thanx !
