Factor the quadratic to:
(x+6)(x+8) = 0 then x+6 = 0 x = -6 and x+8 = 0 x = -8
Using distributive property:
-5(v+9) = (-5)(v) +(-5)(9) = -5v - 45
a you are given the position function
b velocity function is the derivative of position fxn
c time will be when s(t) = 0
d When you have THAT time , substitute that value of 't' in to the velocity function from 'b'
Yah....I had cal 1 cal 2 cal 3 Diffy q Advanced Applied Math....but it was 35 years ago, with no practice since....
BUT I get to re-learn a bit here.....!
Dang....Quasi-almost-so-close !
YOU WIN !!!!!!! Haha ...so ABSOLUTELY true ! I am still laughing !!
Yikes....thanx Chris !
Egad.....that was a long time ago
I THINK:
1 is true
2 not true (I think)
3 Nope ....FIRST derivative of position is VELOCITY....second is ACCELERATION
4 I THINK so....it would be the derivative of a constant...=0
5 I believe that is true
Hmmmm not sure... n f(x)^(n-1) ???
