ElectricPavlov

Last choice.

Standard form   2x^2 - 4x - 16 = 0

Factored   (2x+4)(x-4) = 0

2x+4 = 0           or    x-4 = 0  

x = -2            oro      x = 4

Sustitute in -2  to see if the equation 'works'     then try x= 4 to see if it too, works.....

The third choice.

First Box   x^4 + 2 x^2 y^2 + y^4

Middle box  (add like terms)  2x^4 + 2 x^2 y^2 + 2 y^4

Last box:    (factor out the 2)  2 (x^4 + x^2 y^2 + y^4 )

You're welcome !

4/7 + 1/2 = 8/14 + 7/14 = 15/14   numerator of original fxn = 4

Length   1 1/4 = 10 /8   =  10 cubes  L

width    = 5/8                 =  5 cubes  W

Height = 3/4 = 6/8        = 6 cubes    H

10 x 5 x 6 = 300 little cubes

I think you made a typo....

x^2 + y^2 = 17^2

Factor the right numerator to get:

(t-8)(t+7) / (t-8)   = 3/(t+5)           the term (t-8) cancles out on the right but REMEMBER t cannot equal 8 (would make zero denominator)

t+7 = 3/ (t+5)

(t+7)*(t+5) = 3

t^2 + 12t + 35 = 3

t^2 + 12t + 32 = 0

(t+8)(t+4) = 0            Shows   t = -8 or  -4     the greatest of which is -4