geno3141

This site:

https://math.stackexchange.com/questions/402451/evaluating-a-summation-of-inverse-squares-over-odd-indices

has both the answer and an explanation.

To find the value of s for which:  sec(s)  =  1.0806.

Since  sec(s)  =  1/cos(s):     sec(s)  =  1.0806.    --->     1/cos(s)  =  1.0806

                        Multiply both sides by cos(s)                               1  =  1.0806 x cos(s)

                        Divide both sides by 1.0806                    1/1.0806  =  cos(s)

                         Simplifying                                                 cos(s)  =  0.9254

Now, use your calculator to find the inverse cos of 0.9254.

[Inverse cos  is  arc cos  is  2nd cos]

For what constant k is 1 the minimum value of the quadratic 3x² - 15x + k?

I'm going to find the value of k that will make the quadratic equal to zero and, then, add 1 to get the answer to the question.

Completing the square of:  3x² - 15x

        Factor out the 3:          3(x² - 5x)

        Finding the term that will complete the square:  divide 5 by 2 and square that answer:  (5/2)²  =  25/4  =  6 1/4

This means that   3x² - 15x + 6 1/4   =   3(x - 5/2)²      is a perfect square

and, if you replace x with 2.5, your answer will be zero.

Since you want an answer of 1, you will need to add 1:  3(x - 5/2)² + 1     =     3x² - 15x + 18 3/4 + 1     =    3x² - 15x + 19 3/4

Therefore, let  k = 19 3/4

The second answer is correct.

You begin by placing the opposite of the number (of the divisor) into the box on the top left.

Then, you bring down the coefficient of the squared term (the '2').

Now, you multiply the number in the box (the '5') times the coefficient of the squared term (the '2') and you place the answer (a '10') into the second column. This column now contains a '-1' and a '10; add these together, getting '9'.

Finally, multiply the number in the box (the '5') times the result of the second column (the '9'), getting '45'. Place this number into the third column and add down, getting '49'.

The division results in a quotient of '2x + 9' and a remainder of '49'.

If you are to solve this problem for j and for c, multiply the second equation by 2 and subtract from the first equation.

5j + 6c  =  32                    --->     5j + 6c   =  32

1j + 3c  =  10     --->   x2   --->     2j + 6c  =  20

Subtract                            --->     3j           =  12

Divide by 3                       --->                  j  =  4

Substitute 4 for j in the second equation:  1j + 3c  =  10     --->     1(4) + 3c  =  10     --->     4 + 3c  =  10

                                                             Subtract 4 from both sides                                              3c  =  6

                                                             Divide by 3                                                                        c  =  2

A solution of this set of equations is:  c = 2  and  j = 4.

If  f(x)  =  [x + 1/x - 1]³,  f(x)  is of the form  f(x) = [g(x)]³, so  f'(x)  =  3[g(x)]²·g'(x)

  f(x)  =  [x + 1/x - 1]³     --->     f'(x)  =  3[x + 1/x - 1]³·[1 - 1/x²]

To find f'(2), replace x with 2 in the above derivative, and simplify.  

For the equation  x + 3y  =  -8

                                  3y  =  -8 - x

                                    y  =  (-8 - x) / 3

When  x = 0,  y = -8/3.

For any positive value of x, y will be smaller than  -8/3.

So, the range of y is:  y  <=  -8/3.

If you multiply 14.8 by 5, you will get 64, a whole number.

My understanding of the problem is, even though the series could last 7 games, in this case it lasted only 6 because one of the teams achieved its fourth win in the sixth game.

Since each team has a 1/2 probability of winning each game, each team will have a 1/2 probability of winning the series (this does not depend upon how many games the series actually lasts).

So, the probability that the Giants win is 0.50  (one-half).

Ja! Så, hva er spørsmålet?