hectictar

\(\frac{7.9 \times 10-4}{8} = \frac{79-4}{8} = \frac{75}{8} = 9\frac{3}{8} = 9.375\)

\(x^2+y^2=8x-6y-20 \\ x^2-8x+y^2+6y=-20 \\ x^2-8x+16+y^2+6y+9=-20+16+9 \\ (x-4)(x-4)+(y+3)(y+3)=5 \\ (x-4)^2 + (y+3)^2 = 5\)

So the center is located at (4,-3)

4 + (-3) = 4 - 3 = 1

C = 3.5n²

Plug in what you know.

126 = 3.5n²

Divide both sides by 3.5

126/3.5 = n²

36 = n²

Take the square root of both sides.

√(36) = n

6 feet = n

side length = 6 feet

The tangent of 90º is 1/0, which is undefined.....so maybe it is useful to define it because it is undefined? I don't really know......

Ohhh I can do this one!

\(x^2+y^2=4x+12y-39 \\ x^2-4x+y^2-12y=-39 \\ x^2-4x+4+y^2-12y+36=-39+4+36 \\ (x-2)(x-2)+(y-6)(y-6)=1 \\ (x-2)^2 + (y-6)^2 = 1\)

So the center is located at (2,6)

2 + 6 = 8     :)

Ohhh, in that case...

a = 1, b = 2, c = 1, d = 1, e = 3, f = 3, g = 1

So

\(\frac{ad+be+cf+g}{ag+bf+ce+d}=\frac{(1)(1)+(2)(3)+(1)(3)+1}{(1)(1)+(2)(3)+(1)(3)+1} \\~\\ = \frac{1+6+3+1}{1+6+3+1} = \frac{11}{11} = 1\)

(All that work and the answer is just 1!)

Happy Pi Day!!!!!!!!!!!! 

Anyone planning to eat pie today?

Last year my teacher told us we could bring pie in to celebrate. I remember I thought it would be a good idea to bring in a cake with the entire unit circle drawn on in icing, so I did it!!!

I was looking for a picture but I don't seem to have one :(

You're not wrong! People need to put their parenthesees if they mean them. Parenthesees are really good!

Except apparently the last 2 things aren't really equal in all cases. I wasn't aware of that until now. 

I would also say about 7 hours

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