1.
In all 30-60-90 triangles:
the shortest side—across from the 30º angle = n
the middle length side—across from the 60º angle = √(3)n
the longest side/hypotenuse—across from the 90º angle = 2n
So..... if the shortest side = n = 8
The hypotenuse = 2n = 2(8) = 16 meters
2.
In all 45-45-90 triangles:
both legs—across from the 45º angles = n
the hypotenuse—across from the 90º angle = √(2)n
So...if a leg = n = 5
The hypotenuse = √(2)n = √(2)(5) = 5√(2) ≈ 7.071 inches
3.
x is one of the legs of a 45-45-90 triangle.
The other leg is the hypotenuse of a 30-60-90 triangle.
Both legs are the same length in a 45-45-90 triangle.
So..
Find the hypotenuse of the 30-60-90 triangle when the middle length side = 2√(3)
and that will be the same length as x.
Can finish this one on your own? It is now very similar to problem number 1.
4.
The sin(45º) = the length of a leg in a 45-45-90 triangle when the hypotenuse is 1.
So..
Find the length of a leg in a 45-45-90 triangle when the hypotenuse = 1
and that will be sin(45º)
Can you finish it on your own? It is very similar to problem number 2.
5.
Here is an illustration:

area of hexagon = 12 * area of third triangle.
area of third triangle = (1/2) * base * height
area of third triangle = (1/2) * 6 * orange line
area of third triangle = 3 * orange line
area of third triangle = 3 * √(3)(6)
area of third triangle = 18√3
area of hexagon = 12 * 18√3
area of hexagon = 216√3 ≈ 374.123 sq. cm.