we know that 0.5=1/2 and this is 0.0101010... more than 1/2 and we know that 100/199=0.502512563...,101/199=0.507537688,102/199=0.512562814... so 0.5101010... is in between 101/199 and 102/199 so we have that 0.5101010... is 101/198
Who's a noob?
It's about the likes you have
We have that the long leg of a 30-60-90 trianlge is sqrt3*[short leg] so it is sqrt3*sqrt3*sqrt3*sqrt3 since the *2 and the /2 cancel out so we have (sqrt3)^4/sqrt3 so we have sqrt3^3=3sqrt3 and our final answer is \(\boxed{3\sqrt3}\)
we find that the slope is -1/3 and the y-intercept is (0,1) so the equation is y<=-1/3x+1
we put them into groups like this 100-98=2 like hwat geno3141 said and we have 100/2=50 groups of 2 numbers of 2 so the sum is 2*50=100
I'm not really sure if it's 0 or 40 though
1t is 1*2*5*4=40 so there are 40 combinitions
We can pretend that 99=100-1 and plug it in to get (100-1)*3456 then we use the associative property of multiplication to get 100*3456-356=345600-3456 and we get 342144
