3.8/2=1.9
1.9*680+1.9*720\(\approx 2736\)
using the distance formula, or pythagorean theorem, we have \(\sqrt{0^2+9^2}=9\)
step 1: expand
\(2x(x-1)=2x^2-2x\)
\(2x^2-2x=-50\)
We hen add 50 to both sides to get the quadratic
\(2x^2-2x+50=0\)
Applying Vietas, we have the sum of the roots is \(-b/a\) and the product is \(c/a\) where \(ax^2+bx+c=0\)
so we have \(2/2=\boxed{1}\)
1. 4*12=48
2. 16*-8=-256/2=-128
3. 4*11=44
we sum the two given angles, to get 36+113=149
360-149=211
we see that choice 3 and 4 don't work, because they don't sum to 200, and choice 2 doesnt work because the last digit will be 0, so choice 1 is our answer
\(\begin{align*} f(\sqrt[3]{-8})&=|\lfloor{-2}\rfloor|=2\\ f(-\pi)&=\lceil{-\pi}\rceil^2=-3^2=9\\ f(\sqrt{50})&=\lceil{\sqrt{50}}\rceil^2=8^2=64\\ f\left(\frac{9}{2}\right)&=|\lfloor{\frac{9}{2}}\rfloor|=4\\ 2+9+64+4&=\boxed{79}\\ \end{align*} \)
omighty flec jk
Thank you!
we add 24 to x and we see that equals 3 times x, so our equation is 24+x=3x
now, we shift the x to the right hand side, to get 24=2x
we divide by 2, to get 12=x
our answer is 12
we know from the first 38 hours we traveled 38s miles, because time*speed=distance, so then we have (s+11)*1=s+11, for the next hour. Combining into one equation, we have 39s+11=d
fixed question: A gym charges members 40 for a registration fee, and then 38 per month. You became a member some time ago, and now you have paid a total of 534 to the gym. How many months have passed since you joined the gym?
solution: we subtract 40 from 534 to get 494, and 494/38=13
+201 
