lhyla02

Hey there!

Here we just want to cross out the stuff we are able to until we get to our answer:

\(\frac{18a^{2}b^{3}}{3ab}=6ab^{2}\)

Hope this helped :)

Hey there!

This isn't a maths question... but... Homeostasis, I believe, is maintained by negative loops of feedback.

Hope this helped :)

Hey there!

Here we want to calculate 1x2x3x4x5x6x7x8x9, which is also 9!

Plug this into your calculator, or one online, and you will get yopur answer!

Hope this helped! Let me know how you go! :)

Hey there!!

This is what i would do:
 

\(t=\frac{\sqrt{2d}}{\sqrt{a}}\times\frac{\sqrt{a}}{\sqrt{a}} \)

\(t=\frac{\sqrt{2d}\times\sqrt{a}}{a}\)

\(t=\frac{\sqrt{2}\sqrt{da}}{a}\)

I hope this helped :)

Hey there!

CPhill actually did a nice solution to this problem a few years back! I hope he doesnt mind me linking his solution to this problem :)

https://web2.0calc.com/questions/find-all-cube-roots-of-8i

Hope this helped :)

Hey there!

You can find a circles circumference by multiplying its diameter (or 2*radius) by pi!!

You got this! Hope this helped :)

Hey there!

You can find a circles circumference by multiplying its diameter (or 2*radius) by pi!!

You got this! Hope this helped :)

Hey there!

We know that there is 360 degrees in a circle, so using this we know that the fraction for the blue portion will be:

\(\frac{360-48}{360}=\frac{312}{360}=\frac{13}{15}\)

Hope this helped :)

Hey there!

Here I'm going to assume that the angles and lengths represented by the unknowns are equivalent. Thus we can let them equal eachother and solve for the unknowns. For \(x\)

\(3x+3=6x-18\)

\(3x=21\)

\(\therefore x=7\)

For \(y\):

\(7y-3=2x+4\)    we know what \(x\) is so we can sub that in and solve for \(y\)

\(7y=21\)

\(\therefore y=3\)

Hope this helped :)

Hey there!

From your definitions we know that there are 26 red cards in the deck. I'm assuming that there is no replacement when the first card is drawn. The chance of you drawing a red card first is \(\frac{26}{52}\) then, since a red card is removed from the deck, the chance of getting a second red card is \(\frac{25}{51}\). We then multiply this together to get the probability of this occurring:

\(\frac{26}{52}\times \frac{25}{51} \approx 0.2451 \approx 24.51\%\)

Hope this helped :)

Hey there!

Since the first number cant be zero there are only 9 options (1 thru 9), however for the next seven they can be zero, thus there are 10 options (0 thru 9). for the letters, the first option will be 5 as and the second will be 4 as there is no replacement. This gives:
 

\(9\times 10^7\times 5\times 4=1800000000\)

Thus there are 1.8billion possible student numbers

I could be wrong here but I do believe this is how you do it... Hope this helped :)

Thankyou!

Hey there!

For the left triangle, we can gather that the bottom left unknown = 75 and the top unnkown = 45. From this, and knowing that the flat portions add up to 180, you should be able to find the value of x. Give it a crack and let me know how you go :)

Hope this helped :)

Here we want to multiply the fraction by its conjugate, thus:

\(\frac{10\sqrt{7}}{-1+\sqrt{10}} \times \frac{1+\sqrt{10}}{1+\sqrt{10}}=\frac{10\sqrt{7}(1+\sqrt{10}}{(-1+\sqrt{10})(1+\sqrt{10})}\)

expanding the denomenator comes out as 9. after expanding we get the following

\(\frac{10\sqrt{7}+10\sqrt{70}}{9}=\frac{-10\sqrt{7}-10\sqrt{70}}{-9}\)

I hope this helped :)

Hey there!

Is any of this question cut off? I am not getting any of these 4 answer?

EDIT: nevermind, i'm dumb, give me minute...

Hey there!

Here we know that the angles along A and C will add up to a total of 180. Due to what i know as the Z rule (I don't actually know the correct term for this is), we know that angle 2 will be equal to the unknown inner angle of the triangle near C. Using this, you should be able to find all the angles that you are looking for! Give it a go and let me know how you go.

Hope this helped :)

Hey there!

We know that near H, G, D and C that these angles will add to give 180, we also know that the two angles at the tops of the triangles near F will be equal to eachother. Finally we know that the sum of angles in a triangle is equal to 180. Using this you can find all the angles needed to find angle B. Give it a crack and let me know how you go!

Hope this helped :)

Hey there!

First we expand then can find the asnwer by simplifying:

\((5x^2-3x+5)-(-6x^2+3x+8)\)

\(5x^2-3x+5+6x^2-3x-8\)

\(11x^2-6x-3\)

Hope this helped :)