MathsGod1

I'm getting confused near the end.

On row 14 is where it starts.

Weren't you meant to do 64+12 then take away 15? 

I don't get how you got 3 on row 15?

12-15 = -3 ?

But you're meant to do addition first ..

Cool!

But what is:

x^1/2  

I had to make a new comment.

I coundn't ris losing 20minues of latex.

$$\left({\mathtt{1}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{3}}}{{\mathtt{4}}}}\right){\mathtt{\,\times\,}}{\mathtt{7}}{\mathtt{\,\small\textbf+\,}}{{\mathtt{8}}}^{{\mathtt{2}}}{\mathtt{\,-\,}}{\frac{{\mathtt{6}}}{\left({\frac{{\mathtt{4}}}{{\mathtt{10}}}}\right)}} = {\frac{{\mathtt{245}}}{{\mathtt{4}}}} = {\mathtt{61.25}}$$

YES!!!!!!!!!!!!!!!!!!

I did double check, didn't have to edit it though.

As for the bit where there is a - 

I got confused whether is was negative 6 or taking away 6.

At first i worked it out as a negative then it didn't work out...

Underneath each bracket collum i worked it out. 

I skiped all the workings and went to the final stage (because it's really long and I didn't want the latex to look messy).

If you want i can show my workings and how i got there in the next post - i don't mind! 

Definetly horrible. 

$$\\1\frac{3}{4}\times 7 +8^2-6\div \frac{4}{10}\\\\
=1\frac{3}{4}\times7+8^2-6\div\frac{4}{10}\qquad(There\;are\;no\;Brackets)\\\\
=1\frac{3}{4}\times 7 +8^2-6\div\frac{4}{10}\\\\
=1\frac{3}{4}\times7+\mathbf{8^2}-6\div\frac{4}{10}\qquad(Exponents)\\\\
=8\times8=64\\\\\$$

$$\\=1\frac{3}{4}\times7+64-6\div\frac{4}{10}\\\\
=1\frac{3}{4}\times7+64-`\mathbf{6\div\frac{4}{10}}\qquad(Division)\\\\
=\frac{6}{1}\times\frac{10}{4}=15\\\\
=1\frac{3}{4}\times7+64-15\\\\
=\mathbf{1\frac{3}{4}\times7}+64-15\qquad(Multiplication)\\\\
=\frac{7}{4}\times\frac{7}{1}=\frac{49}{4}\\\\
=\frac{49}{4}+64-15\\\\
=\mathbf{\frac{49}{4}+64}-15\qquad(Addition)\\\\
=\frac{49}{4}+\frac{256}{4}=\frac{305}{4}\\\\
=\frac{305}{4}-15\\\\$$

$$\\=\mathbf{\frac{305}{4}-15}\qquad(Substraction)\\\\
=\frac{305}{4}-\frac{60}{4}=\frac{245}{4}
=\frac{245}{4}$$

$$\frac{245}{4}$$

Another way.

$${\frac{{\mathtt{195}}}{{\mathtt{10}}}}{\mathtt{\,\times\,}}{\mathtt{3}} = {\frac{{\mathtt{117}}}{{\mathtt{2}}}} = {\mathtt{58.5}}$$

Note that Prime factors is only prime numbers.

E.g. 15 prime numbers are 15, 1, 3, 5

Prime factors of it . 5 is a prime number .  3 is a prime number . 1 is technically not a prime number and 15 isn't.

LCM= Lowest common multiple

And you're finding the factors of 12 and 4 to do this.

You can present this as the tree form.

Using that information you can answer the question.

4 - lowest factor (not including 1) is 2

12 -lowest factor (not including 1) is 2

Thats the LCM of those two.

AWESOMEE got the all!

1. Be prepared

2. Always make sure you read the question right.

3. Study

4. Use your time wisely

5. Check your answers

You might think I'm a being a typical teacher but seriously! These are vital rules. 

Every times when I used to do tests i always missed out marks with daft answers on easy questions.

Don't be nervous, know you're gonna ace the test.

Read the question right seriously, so many times I've done that...

Study on the topic drill the notes into your head!

Don't spend too much time on a question come back to it later, otherwise by the time you get it times up. Use your time on the big mark questions.

The relates to 2. along with reading it check a double check is always safe!

LOL.

Kinda sexist...

But we all know this isn't true. Look who runs the forum!!!