Melody

$$\\\boxed{a^3+b^3=(a+b)(a^2-ab+b^2)}\\\\
x^3+\left(\frac{1}{8}\right)^3
=\left(x+\frac{1}{8}\right)\left(x^2-\frac{x}{8}+\frac{1}{64}\right)$$

I'll give you more points too saseflower because you always give such good answers:D

Anon's answer is correct. :)

Here is another answer :)   they will give the same answer.

$$\\1.06^x=2\\\\
log(1.06^x)=log2\\\\
xlog1.06=log2\\\\
x=\frac{log2}{log1.06}\\\\$$

the web2 calc is really good  for many things but its graphing features are not great.

I suggest that you use

$$\\12<3y<6 \\
4

this has no solutions.

if 4<y    then     y>4  

Y cannot be  greater than 4 and less than 2 at the same time.  :)

Use Desmos

Maybe this will help.  There are a lot of good resources on the net. 

Hi SoulReaper.  It is easier to multiply both sides by 10 first to get rid of all the fractions.

But the answer will be the same.  :))

I'm all dolled up, packed my essential.

I feel soooo good

Who's on the menu tonight.

Where's that Zee-man

I am so excited (and hungry).