Melody

Hi Sadpumpkin,

Hopefully this will cheer you up a bit  :)

5x-7 = +1(5x-7)

and

7-5x= -1(5x-7)

So the  common factor is   5x-7      OR   7-5x   is you prefer

=((2*Y^2)^(5/3))/((4*Y)^(2/3))

\(\frac{(2Y^2)^{5/3}}{(4Y)^{2/3}}\\ =\frac{(2^5Y^{10})^{1/3}}{(4^2Y^2)^{1/3}}\\ =\frac{(2^5Y^{10})^{1/3}}{(2^4Y^2)^{1/3}}\\ =\frac{(2Y^{8})^{1/3}}{(1*1)^{1/3}}\\ =(2y^8)^{1/3}\\ =\sqrt[3]{2y^8} \)

It is undefined.

Quadrilaterals are 4 sided polygons.

the pic is from this site:

How many people did he share his half potoato with?

Anyway he'd have 1.5 potatoes plus a bit more. ://

Thanks 315

Thats a great ego boost on which I will start my morning. :)

Plus

I am always pleased to help. :D

yes

post the question!

Arcsin(sin(40)*sin(23.22) - cos(40)*cos(23.22)*cos((360*18)/24 - 88))

asin(sin(40)*sin(23.22) - cos(40)*cos(23.22)*cos((360*18)/24 - 88)) = 73.135097037446 degrees

I just put it straight into the web2.0calc      

Thanks Omi :)

Omi thinks that you may have forgotten a ^ symbol.

She has answered a possible alternate version of your question.