Melody

I was going to look at this one but the question is getting old and you are not a member (members get emailed about new answers if they want to be)  Also members havew the question automatically placed in their watch list and it shows if there is an unread answer.

Anyway - being a guest it means you likely won't even find the question or see the answer so what is the point?

Here you go - I did it for you

OR look it up on the net.

f ''(x) = −2 + 18x − 12x^2,    f(0) = 8,    f '(0) = 14

find f(x)=

\(f ''(x) = −2 + 18x − 12x^2\\ f'(x)=-2x+9x^2-4x^3+k\\ f'(0)=14\qquad so\qquad k=14\\ f'(x)=-2x+9x^2-4x^3+14\\ f(x)=-x^2+3x^3-x^4+14x+c\\ f(0)=8 \qquad so\qquad c=8\\ f(x)=-x^2+3x^3-x^4+14x+8\\ \)

You know Struggling Student, it would be polite for you to acknowledge the answer that I have given you. 

x = 1/6 (7+(721-84 sqrt(57))^(1/3)+(721+84 sqrt(57))^(1/3))

\(x = \frac{1}{6}\left[7+(721-84 \sqrt{57})^{1/3}+(721+84 \sqrt{57})^{1/3}\right]\\ \)

You can get an approximation on your calculator but this cannot be simplified.

1/6 (7+(721-84 sqrt(57))^(1/3)+(721+84 sqrt(57))^(1/3)) = 3.7490191400643459

Yes, I commented on asinus's post in the German forum.  Thank you :)

Hi asinus,

I have sent a message to admin. :)

Maybe you can get in with a different browser - I use Chrome and i have not had any problems. :/

Hallo Asinus,

Ich habe eine Nachricht an admin. :)

Vielleicht kann man sich mit einem anderen Browser - ich benutze Chrome und ichhabe keine Probleme gehabt. :/

I have sent a message to admin  :)

ok :/  I will see what I can do.