Melody

Square root of 8.1x10^5

= sqrt (8.1×10×10^4)

=sqrt (81×10^4)

=9×10^2

=900 feet

Area=15×8.1×10^5

Area=121.5×10^5

Area=1.215×10^7  feet squared

Put it into Wolframalpha and then copy and paste the link into a new post on this thread. 

Then we'll be able to see what you have done and we will probaby see why the answer is different.  :)

If you were a member you could message us the link as older posts can sometimes be hard to find ://

But we will probably see it anyway.  :)

ONE

sin200 (degrees) = -sin(200-180) = -sin20

It is not infinity.  It is just too large for the calculator to calculate. 

\frac{((1-\sqrt{2})+(1-\sqrt{2}i)}{1-\sqrt{2}i}

\(\frac{((1-\sqrt{2})+(1-\sqrt{2}i)}{1-\sqrt{2}i}\\ =\frac{(2-\sqrt{2}-\sqrt{2}i)}{1-\sqrt{2}i}\\ =\frac{(2-\sqrt{2}-\sqrt{2}i)}{1-\sqrt{2}i}\times \frac{1+\sqrt2i}{1+\sqrt2i}\\ =\frac{(1+\sqrt2i)(2-\sqrt{2}-\sqrt{2}i)}{1^2-(\sqrt{2}i)^2}\\ =\frac{(2-\sqrt{2}-\sqrt{2}i)+(\sqrt2i)(2-\sqrt{2}-\sqrt{2}i)}{1-(2*-1)}\\ =\frac{(2-\sqrt{2}-\sqrt{2}i)+(2\sqrt2i-\sqrt{2}\sqrt2i-\sqrt{2}\sqrt2ii)} {3}\\ =\frac{2-\sqrt{2}-\sqrt{2}i+2\sqrt2i-2i+2} {3}\\ =\frac{4-\sqrt{2}+\sqrt2i-2i} {3}\\ =\frac{4-\sqrt{2}+(\sqrt2-2)i} {3}\\ \)

Yes guest is right. My calc gave me some strange results.

We both did it the same way though. :)

Thanks guest :)

This cannot be simplified :)

If y=10*3^x how do i find the double constant using log?

What are you talking about ?

Thanks Tertre, that is a really nice comment :)