Yes Chris wouild be right I read the quesiton incorrectly.
Find the distance (departure) to the nearest whole mile between initial position 50° 00' N 02° 00' W and 50° 00' N 01° 26' W
I read the second one as 26 degrees west INSTEAD OF 1 degree and 26 minutes west.
I will do the last bit a again. I am assumingthat the earth is a perfect sphere - which it isn't.
And that the 2 points are both at sea level.
The difference in longitude is 34 seconds.
\(distance = \frac{34}{360*60}*2*\pi*2544.8=25 miles\)
Now wolfram alpha and I agree 