Hi 8MP and Ginger,
Since Ginger has not expalined how she worked out this answer I have decided to give it a go. :)
Maybe this is what she did....
1) The reflection. Maybe this was the best place to start, it seem right because it would orient the star so that when it was rotated anticlockwise it would have D on the top.
2) Now just looked at the B point. I'd want to move it so that (afterwards) when it was rotated 90 anticlockwise the B point would end up on the negative x axis. But there obviously had to be a dilation to get B into the correct position first.
Now when B was rotated about (5,0) it would need to be on the x axis.
So I draw the line x=5. B would need to be moved to a point on that line.
3) I'd then my attention to the dilation that would be needed.
I drew a line from the centre of the dilation (-5,0) through B’ and subtended it till it intersected with x=5
That point of intersection would need to be the new B value. i.e. B’’
4) B’ was the point (0,9.5)
I could see from the diagram that B” was the point (5,19)
So it was clear that B’’ had to be twice as far as B’ from the centre of the dilation.
So I needed a dilation factor of 2
Now I did the dilation and the 3rd star was born.
3) Now I just had to rotate it 90 degrees anticlockwise to get B onto the x axis.
Lastly Ginger had to counter the enlargement so she implemented a dilation of 0.5 centred at (-5,0)
Here is the pic

Is this how you thought about it too Ginger?