Melody

\(7-7(2+3x)\\ =7 +\;\; -7(2+3x)\\ =7 +\;\; -7*2\;\;+\;\;-7*3x\\ =7 +\;\;\; -14\;\;\;\;\;+\;\;-21x\\ =7 \;\; -\;\;\; 14\;\;\;\;\;-\;\;\;\;21x\\ =\quad -7\;\;\;\;\;\qquad -\;\;\;\;21x\\~\\ =-7-21x\)

n can be any multiple of 6 so the sum is infinite.  

This answer is compeletely  wrong so skip it.

x^4-36 

this is the difference of two squares 

so

\(= (x^2-6)(x^2+6)\\ =(x-\sqrt 6)(x+\sqrt 6)(x^2+6)\)

You can only go further than this if you accept complex (imaginary) roots.

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64c^3+1

This is the sum of 2 cubes     \((4c)^3+1^3\)

I expect you can look at the link below and work this one out for yourself.   :)

But that  won't tell you if it is completely factored RP. 

Alan is right, the leading coefficient of g(x) must be     \(\sqrt{\frac{8}{5}}\;\;i\)      

We both think that there is a mistake in the question.  

Lets think about an answer now..

The total area of the boxes is 4*3 + 2*8 + 2*11 + 1*23 + 1*19 + 4*2 = 12+16+22+23+19+8 =  100

So each little box represents 10 mice.

There are 12 squares in the less than 10g region

So 120 of the mice had a birth weight of under 10g

The second answer is the correct one.

Welcome to the forum kminery.

Sorry I wasn't here to continue explaining Panda, I know you have reposted. I hope that you get it now :)