Melody

Why havn't you responded?  :/

Mmm that should be a concern to you.

Substitute x=-3 and y=2 into the equation and see if the left side is equal to the right side.

If it is then (-3,2) satisfies the equation which means (-3,2) lies on the circle.

1) Now you can do that bit by yourself.

2) Now you need to know the centre of the circle. (look up the equation of a circle and see if you can work that out yourself)

3)Find the gradient of the line joining the centre to the point P

4)The tangent will be at right angles to this radius so what is its gradient?

5) Now you have a gradient and a point on the tangent so you can find the equation of this line.

I will assume that you mean

f(x) = sin3xcosx/(tan2x+1)    this has no global maximum   (ref: Wolframalpha)

so maybe you mean  

f(x) = (sin3xcosx/tan2x)+1       (yes I know this is how it should be interpreted bum a loy of people make mistakes here)

I spent ages working on the first interpretation,  I haven't got the energy to look at this second one at present but Wolfram Alpha says the maximum is  2.5

That is pretty neat Rom.   

Don't you know how to show that that point is on the circle?

it would have to be negative.

you needed to specify that it was a binomial question

put

nCr(223,221)    into the web2 calc and press =

Then just do it with a calculator.

Most calc have an    \(^nC_r\)     button

the first one is just

\(4\;^nC_r\;0+ etc\\ \text{Anyway you should know that }^nC_r\;0 =1\)

On the web 2 calc just write in

nCr(4,0) +       etc

This is not a question.

ARe they meant to be binomial coefficients or vectors or what?