\(12 tan^3 x = 4 tan x\\ let\;\; y=tanx\\ 12y^3 = 4y\\ 12y^3 -4y=0\\ 4y(3y^2 -1)=0\\ 4y(\sqrt{3}y -1)(\sqrt{3}y +1)=0\\ 4y=0,\;\;\;or\;\;\;\sqrt{3}y -1=0\;\;\;or\;\;\; \sqrt{3}y +1=0\\ y=0,\qquad y=\frac{1}{\sqrt{3}}\qquad or\qquad y=\frac{-1}{\sqrt{3}}\\ tanx=0,\qquad tanx=\frac{1}{\sqrt{3}}\qquad or\qquad tanx=\frac{-1}{\sqrt{3}}\\ x=n\pi,\qquad x=n\pi\pm \frac{\pi}{6}\qquad n\in Z\)
With the first on I would just graph it.
Put the time on the horizongal (bottom) axis and temperature on the vertical axis.
Then you can just read the answer of the graph.
How did you get those answers Fiora? there is no hourly rate given ....
I don't think your notation is correct. I do not know what it means anyway .....
I think it is $28,187.50
0.75*0.4=0.3 and 0.3*57000= $22500
0.75*0.6=0.45 and 0.45*15000=$6750
0.25*0.45=0.1125 and 0.1125*15000=$1687.50
0.25*0.55=0.1375 and 0.1375*-20000 = -$2750
When all of those are added together I get $28187.50
Hi Rose, nice to see you here again :)
Jjennylove DO NOT EVER DELETE YOUR QUESTIONS !
It is extremely rude and some members have already been blocked from this forum for doing this.
You do not want the next blocked person to be you !
It is very nice to see you interacting Panda but it would be nice to also see you say 'thanks' to Rom :)
what is (x + 2)2 + (y + 1)2
I expect you mean
what is (x + 2)^2 + (y + 1)^2
\((x + 2)^2 + (y + 1)^2\\ =x^2+4x+4\quad + \quad y^2+2y+1\\ =x^2+4x+y^2+2y+5\\ \)
Thanks Chris :)
+118613 
