Melody

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Melody  11 февр. 2022 г.
 #1
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+1

Take a look at this old post and try to learn from it :)

 

https://web2.0calc.com/questions/how-do-you-find-a-power-function-that-is-graphed

 

The numbered questions refer to the graphs at the bottom of the post. 

(only the first line of picts, going from left to right. )

29 мар. 2019 г.
 #1
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28 мар. 2019 г.
 #5
avatar+118725 
+3

Hi Rom, I am not trying to hijack your question, I started this ages ago.

I will post it, even though you have already given a good answer.

---------------

 

Hi SmartMathMan :)

 

I think you are expected to memorize the speed of light. 

You can google it of course, which is what i just did.

 

https://goo.gl/en2ZTc

 

So we have the speed of light = 3*10^8   m/s

 

1 Herz means that the wave passes a point in seocnd.  That is  1 Herz=1 wavelength/sec.

Your wave has  600THz which is     600*10^12 wavelengths/sec

 

You want to know wavelegth

 

For any wave

speed of wave (m/s)= wavelength (m)* number of waves/sec

 

In this case the speed is the speed of light which is 3*10^8 m/s

the wavelength is unknown

The number of waves per sec is the number of Herz.

     600THz = 600*10^12 Herz = 6*10^14 Herz       (6*10^14 waves pass a certain point each second)

 

speed of wave (m/s)= wavelength (m)* number of waves/sec

\(c=\lambda * v\\ \lambda=c\div v\\ \lambda=\frac{3*10^8\;m}{sec}\div\frac{ 6*10^{14}waves}{sec}\\ \lambda=\frac{3*10^8\;m}{sec}\div\frac{ 6*10^{14}waves}{sec}\\ \lambda=\frac{3*10^8\;m}{sec}\times\frac{sec}{ 6*10^{14}waves}\\ \text{the secs cancel out leaving}\\ \lambda=\frac{3*10^8}{ 6*10^{14}}\frac{metres}{wave}\\~\\ \lambda=\frac{3*10^8}{ 6*10^{14}}metres\\~\\ \text{the word 'wave' is just understood} \)

.
28 мар. 2019 г.