Melody

Thanks Tiggsy.    

I shall learn from your answer properly in the morning :)

GOOD WORK !!    

I added to your graph :)

So what is the polynomial?  Did you graph it using desmos to check your answer?

squares that end in 6 must be of the form

\((10n\pm4)^2\)     where n is an interger 

\((10n\pm4)^2\\ =100n^2\pm80n+16\\ =100n^2+10\pm80n+6\\ =100n^2+10(1\pm8n)+6\\ \text{8n can end in any even number so }1\pm8n \text { can end in any odd number}\\ \text{So the 10s place value can have any odd digit.} \)

You didn't offend. I am just stating that your title is incorrect.

It is better if titles reflect the content of the question.

And the content of this questions is

Statistics    OR    Normal distributions     OR       Using Z scores.

Personally I think   'Using Z scores with normal distributions'    would be a very good title.

Yep, that is what Tertre means :)

That is rather difficult to decipher but have you worked it out?

Your question is statistics. It has absolutely nothing to do with calculus.

Hi ThorganHarzard

Welcome to the   Web2.0calc   forum       

That is a very impressive answer but you lost me at the ''=2R"   bit.    What has it to do with the circumscribed circle?

I am not questioning your knowledge, I just don't understand.

No you can't .