Melody

Forget about formulas for the moment.

EXPLAIN to me why 24 is the correct answer for part a!

Well show me how you did part a?  And tell me if you really understand? 

Part b is exactly the same idea.

What do you think the answer is guest?  What was the maximum you could work out?

thanks guest, I hope you understand it :)

ok

Here is how I would present the answer.

\(y=4^{2012}\\ log_{10} \;y=log_{10} \;4^{2012}\\ log_2 \;y=2012\;log_2 \;4\\ log_2 \;y=2012*2\\ log_2 \;y=4024\\ \frac{log_{10}\;y}{log_{10}\;2}=4024\\ log_{10}\;y=4024*log_{10}2\\ log_{10}\;y\approx 1211.344703\\ y\approx 10^{1211.344703}\\ y\approx 10^{0.344703}*10^{1211}\\ y\approx 2.211581763*10^{1211}\\ \)

Yes I know there are calculators online that can do it.

I do not think that this is how guest was expected to answer this question.

I asked you if you knew how to do it with a standard old fashioned calculator. (or with the web2.0 calc if you want)

Can you do it with an ordinary old fashioned calculator?

I can but I am asking guest answerer if he/she can.

Please answer a question like this with another question to make the aker interact or think a little for themselves.

Maybe the asker might even learn somthing then.

Like you coulod say.

What is    |-4|   ?

and what does this sign     \(\le\)    mean?

What have you done towards answering this question?

Great work CalculatorUser!      

You maths is excellent,

Just for a slightly different presentation I could say:

\(C=2\pi r\\ \frac{C}{2\pi}=r\\ \frac{C+1}{2\pi}=\frac{C}{2\pi}+\frac{1}{2\pi}=r+\frac{1}{2\pi} \)

So if the circumference is increased by 1 unit, the radius is increased by  \(\frac{1}{2\pi}\;units\)

So if the circumference is increased by 1 metre, the radius is increased by \(\frac{1}{2\pi}\;metre\)

And this equals an approximate radius increas of  0.159 metres or approx  16cm

This distance between the 2 concentric circles will always be the same.

 It does not matter how big or small the original circle is.