Melody

Thanks for showing us Heureka.

That is a great solution!

That is a really neat solution Heueka !  Thanks.  

I will test your answer,

Testing for n=1

\(f(k)=k^3-\frac{3k^2}{2}-\frac{5k}{2}+3\\~\\ f(1)=1^3-\frac{3*1^2}{2}-\frac{5*1}{2}+3\\ \quad f(1)=1-\frac{3}{2}-\frac{5}{2}+3\\ \quad f(1)=0\ne 1^3 \)

Maybe I made a mistake but your formula does not appear to work.

Hi Guest,

It was NewMember, the asker, who voted your answer down.

(I'll give you my up point but it will only take your answer back to zero, sorry.)

It is the way some ignorant people respond when they do not understand an answer.

They should of course just ask you for further explanation or simply say they do not understand.

To be honest, I do not understand you answer either. Maybe it is right, I do not know.

I am not really asking you to explain I am just stateing a fact.

Thanks for the input guest  

There are glitches with the newest updates.

Hopefully admin will sort them all out soon.

I can't blame admin for disallowing ad blocking. It is the only way that sites are able to pay for themselves.

Hectictar just told me that another way to deal with this issue is to change the word  questions   in the address by to answers

That sounds like a neat alternative.  She is not sure if it always will work though.

Thanks Hectictar.  

Thanks guest. :)

Thanks Alan and guest.  

Some time maybe I will work out why mine is wrong.

It is always good to have the correct answer anyway.  

What would we do without your Monty Carlo simulations.  They really ae very useful !

Hi Sadaatkhan,

It is good to see you haviing a go ... but...

Your woking is not correct

(n-1)^3 is not n^3-1

U for union