Melody

Какое уравнение

This is what you have written.  Is it what you actually mean?

\(\dfrac{30\sqrt{5-4\cos\theta}\;-1}{5\cos\theta}\times 2\cos\theta =10\)

Suppose g is a linear function such that g(1.2) = 3.3 and g(-3) = 7.2. Find the equation for g. (Use x for the variable. Round equation parameters to two decimal places.)

7.2-3.3=3.9

-3- -1.2 = -1.8

gradient = 3.9/-1.8 = -13/6  = -2.1666666666666667  = -2.17

g(x)=mx+b

g(x)=-2.17x+b

(1.2, 3.3)

3.3= -2.17*1.2 +b

b=3.3 + (-13/6)*1.2 = 0.7

g(x)= -2.17x + 0.7

Thanks very much guest   

I am reasonably sure I have seen Heureka do this before but I  cannot remember how   

Heueka, if you see this can you show us again, please?

Hey, Bioplant, 

You appear to be a good forum member but .....

How about giving Hectictar some points for her massive effort here.

Thanks for your great answers Hectictar.  

Why don't you just say what you want to say in plain English?

Better still if you believe you are knowledgable why don't you just answer the question yourself.

Why are you hiding behind anonymity?  

People who make snide comments behind a curtain of anonymity usually have no idea of any relevant thing.

If it is a 2 tail test I do not know what the answer is. I'd have to watch the next video I guess.

Golf-course designers have become concerned that old courses are becoming obsolete since new technology has given golfers the ability to hit the ball so far. Designers, therefore, have proposed that new golf courses need to be built expecting that the average golfer can hit the ball more than 255 yards on average. Suppose a random sample of 166 golfers be chosen so that their mean driving distance is 259.5 yards, with a standard deviation of 44. Conduct a hypothesis test where H0:μ=255 and H1:μ>255 by computing the following: (a) test statistic (b) p-value p= (c) If this was a two-tailed test, then the p-value is

\(\mu=255\\ n=166\\ \bar X=259.5\\ S=44\\ Test \;Stat \;is \;Z\\ Z=\frac{\bar X-\mu}{\left(    \frac{S}{\sqrt n}   \right)}\\ Z=\frac{259.5-255}{\left(    \frac{44}{\sqrt {166}}   \right)}\\ Z=1.318\\ \\~\\ H_0:\quad \mu=255\\ H_A:\quad \mu>2.55\\ \\~\\ P(Z>1.318) =P(Z<-1.38) \qquad \text{You can use either}\)

Maybe you have to use a given table.

I like this site.