Melody

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Имя пользователяMelody
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Melody  11 февр. 2022 г.
 #2
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This site will help you.

 

https://www.purplemath.com/modules/hyperbola.htm

 

You have to start by getting it in the form

 

\(\frac{(y-k)^2}{a^2}-\frac{(x-h)^2}{b^2}=1\\ (h,k) \text{ is the centre}\\ \)

 

ALSO ..  Here is a youtube clip that looks fairly comprehensive.

https://www.youtube.com/watch?v=h5aVROOmI-Q

7 сент. 2020 г.
 #1
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0
7 сент. 2020 г.