Melody

Thanks catmg  

One question per post.

You should not be asking anyone to do your homework for you.

You are supposed to post one question and learn from any answer  BEFORE you ask a second question.

And please include a direct link,

or better still, 

write the question or upload a picture of the question directly to the forum.

Suppose that p  is prime and \(1007_p+306_p+113_p+125_p+6_p=142_p+271_p+360_p\).

How many possible values of  p  are there?

I don't think that there are any....

Since there are numbers up to 7 in there, the base, p,  would have to be 11 or more.  (because it is prime)

Looking at just the last digit.

7+6+3+5+6=27                               2+1+0=3

27=3+24

This means that p must be 24 or less (not that that matters)

Anyway,

prime factors, 11 or bigger, of 24 don't exist.

So I think that there are no possible values of p that will satisfy this.

Why can't you become a member and ask him yourself?

I would be happy to give you hints but I haven't got a clue.

Maybe appeal to Heureka....   But, as a guest, it is almost impossible for you to ask anyone directly.

I think

\(\frac{dx}{dt}=2cos(2t)\\ \frac{dy}{dt}=-2sin(2t)\\~\\ \frac{dy}{dx}=\frac{dy}{dt}\cdot \frac{dt}{dx}=-2sin(2x)*\frac{1}{2cos(2x)}=-tan(2x)\)

I admit it. I don't know. 

See if you can find a logic error.   

J stands for the number or marbles Jordan has at the beginning.

The ambiguity is still there.  Are you English as a second language?

anyway, I think you want me to interpret it the way that I did interpret it and I do not think that the fractions/proportions are possible.

Please do not put 'asap' or similar in your questions.  It makes me less likely to answer. Your questions are not more important than anyone elses. 

I have added to the initial thread...