Melody

ok Thanks for answering.

Set these questions out very logically and methodically.  It will help you think each one through properly.

Start with one or more pics to illustrate what is happening.

Here is my initial condition pic with working.  A little more elaborate than what you need.

v is vertical velocity

u is horizontal velocity

initial height = +3feet

acceleration is gravity and it stays the same all the time at 32feet/sec^2  but it is pulling down so it is negative.

And it only affects vertically movement.

\(\frac{dv}{dx} =-32\)

Wind and air resistance is ignored for you so there is no horizontal forces that you need to worry about so what is horizontal acceleration?

here is a clip that might help

If you have problems doing those things then talk to us.

We usually respond really well when people interact with us.

We just don't like to feel that we are doing people's homework and they are taking our answers and often not even trying to understand them.

Why don't YOU post what YOU have tried? 

You can take a photo of your diagram and upload it.

one question per post and one question at a time.

It looks like you are just asking people to do your homework for you.

Ok I have commented on the other thread.

I accept your apology but I do not think that you actually read my response at all.

You certainly have not attempted to answer any of my questions.

ok, perhaps you have a major problem with reading and interpreting questions. Although I doubt you seriously read my response.

I did not ask you how to get to the final answer.

I asked you to tell me the initial conditions.

I asked you for the initial vertical speed, the initial horizontal speed, the initial acceleration, the initial vertical and horizontal displacement.

You still have not given me those. Nor have you discussed them in any way.

You cannot seriously understand your original question if you cannot answer my questions. 

Thanks EP.

These might also help   

4X=35N+1   where N is an integer and x is between 0 and 34

4*9=35+1     (by inspection)

so  \(4^{-1}=9 \mod{35}\)

I don't know if this is the only answer  

Thanks Jugoslav :)

here is the original thread.  NaturalDisaster failed to say so but this is a repost.