Melody

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Имя пользователяMelody
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Melody  11 февр. 2022 г.
 #1
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+3
16 сент. 2014 г.
 #1
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+10

I had no idea so I consulted Wolfram|Alpha

 

http://www.wolframalpha.com/input/?i=y%27%3D4y%5E2

 

If you want an asymtote at t=7 then  

c1-4*7=0

c1=28

$$y(0)=\frac{1}{28-4*0}=\frac{1}{28}$$

 

I really am not sure that this is right.  I'm having a hard time getting my head around it.

16 сент. 2014 г.
 #1
avatar+118733 
+5
16 сент. 2014 г.
 #1
avatar+118733 
+5
16 сент. 2014 г.