MWizard2k04

\(p = \frac{2q^2-1}{3q^2+2} \\ \frac{1}{2} = \frac{2q^2-1}{3q^2+2}\\If \frac{a}{b}=\frac{c}{d},\quad then \,ad=bc. \\ 1(3q^2+2)=2(2q^2-1)\\Simplify\, and\,you\,get:\\ -q^2+4=0 \\ Using\,quadratic\,equation\,method,\, \\ we\,end\,up\,with:\\ q= \pm 2\)     

We use the brackets for order of operations.

In this order

{ [ ( ) ] }

3√10 (root form)

9.487 (decimal form)

Why did you change your text color to white? This is not right. Yo do not need to be fancy here.

If she started with 5 feet, she then cuts off 3³/₄ feet to make a hair bow, being left with 5 - 3³/₄ = 1¹/₄ feet.

Then she cuts off ⁵/₆ feet to make a border on a scrapbook page, being left with

1¹/₄ - ⁵/₆ = ⁵/₄ - ⁵/₆

                = ¹⁵/₁₂ - ¹⁰/₁₂

                = ⁵/₁₂ feet.

If she needs to cut 2 ¹/₃-feet pieces, she will need 2(¹/₃) = ²/₃ feet

                                                                                           = ⁸/₁₂ feet.

She does not have enough ribbon since ²/₃ > ⁵/₁₂. 

Assume each beautician has almost equal number of requests.

95 ÷ 4 = 23 R 3

Assume Kurt has more requests than Jim.

Let Jim be D.

Let Kurt be C.

24 - 23 = 1

She has 1 more.

\(n = {log}_{1.005} \,50 = 784.3589866409396 \\ ≈ 784.36 (2dp)\)