3. My logic for this problem might be flawed, but let me give it my best shot.
If One side of the bottom layer of a triangular pyramid has 11 balls,
The first layer has 1 ball
The Second layer will have \(3 = (1 + 2) \)balls
The Third layer will have \(6=(1 + 2 + 3)\) balls.
The Fourth layer has\( 10=(1 + 2 + 3 + 4)\) balls.
The Fifth layer will have \(15=(1 + 2 + 3 + 4 + 5)\) balls
The sixth layer there are\( 21=(1 + 2 + 3 + 4 + 5 + 6)\) balls
So there will be \(28,36,45,55 \quad \text{and} \quad 66 \) balls in the remaining layers.
So, adding the total number of balls up, we get
\(1 + 3 + 6 + 10 + 15 + 21 + 28 + 36 + 45 + 55 + 66 = 286 balls.\)
So 286 is the answer.
Again, not sure about this one, should be right.
Thanks! :)