Oofrence

A parabola with a positive a value has a minimum point, meaning that this problem is referencing the parabola in the top right. The vertex of the top right one is (3,2) (B)

1. The length of the larger rectangle is 4, and the smaller one is 2. The width of the large rectangle is 2, and the smaller one is 1.

4/2 = 2/1 = 2

The scale factor of the similar figures is  2:1 (B)

2. The square has area of 144 cm^2, meaning that it has side length 12. This means that the diameter of the circle is 12, so the radius is 6

The formula for the area of a circle is πr^2. 

Area = π36, or 36π cm^2 (E)

1. If g(x) = 3x^3 - 4x^2 + 5, find g(-2).

3(-2)^3 - 4(-2)^2 + 5 = 3(-8) - 4(4) + 5 = -24 - 16 + 5 = -35 (B)

2. If f(x) = -x + 4 and g(x) = x^2 - 5, then g(f(-1)) = ?

f(-1) = 1+4 = 5

g(5) = 25 - 5 = 20 (E)

3. If f(x) = x^2 and g(x) = 3x + 1, then f(g(2))= ?

g(2) = 6 + 1 = 7

f(7) = 49 (E)

4. If f(x) = - 2x^2 + 2x - 3, what is f(5)?

f(5) = -2(25) + 10 - 3 = -50 + 10 - 3 = -43 (B)

C is the right answer. X can only be between -6 and 2, which none of the other graphs show.

True.

The absolute value of -4 is 4, and 4 is equal to 4

what's the point of repeatedly posting this exact same copy pasted post?

hey this is an aops question

-1,-2 is the vertex, so you can make it into the vertex form

y = a(x+1)^2 - 2

then plug in 0,-1

-1 = a - 2

a = 3

My computer says that the website is p**n/illicit

hey that's my iq

nope