PocketThePenguin

Nevermind, I got the answer, which was 1458.

can you explain what e is?

looks like that's wrong

erm... that's incorrect

K = 2.

I found this on quora. Look there for a VERY detailed explanation.

https://www.quora.com/Let-k-be-a-positive-real-number-The-line-x-y-k-and-the-circle-x-2-y-2-k-are-drawn-What-is-k-so-that-the-line-is-tangent-to-the-circle

The answer is -1.

let's first start with small numbers, i^1 + i^2 + i^3 + i^4. Assuming in your case i is the imaginary number, I'll start by calculating that. i^1 is just i. i^2 is -1, i^3 is -1(i) which is -i, and i^4 is -i(i) which is -i^2 which is -1(-1) which becomes 1. Continiuing to calculate these, you'll find that there's a pattern.

i^1 = i                   i^5 = i

i^2 = -1                 i^6 = -1

i^3 = -i                  i^7 = -i

i^4 = 1                  i^8 = 1

The powers of i repeat in groups of 4. 

Now that we've found out the pattern, we'll calculate yours. 99/4 leaves a remainder of 3. So then we have i^97 = i, i^98 = -1, and i^99 = -1. The i and -i cancel out, so you're left with the answer -1.

First find the sum of the numbers.

Also, since 0 has no value, I'll take it out for now.

The number series 1, 2, 3, 4, . . . . , 98, 99.
The first term a = 1
The common difference d = 1
Total number of terms n = 99

apply the input parameter values in the formula
Sum = n/2 x (a + Tn)
= 99/2 x (1 + 99)
= 9900/2
1 + 2 + 3 + 4 + . . . . + 98 + 99 = 4950

Therefore, 4950 is the sum of positive integers from 1 to 99.

Next find the average.

The amount of numbers = 100

4950/100 = 49.5

So your final answer is  49.5