proyaop

Please post your question if you need help... LOL

1.4268292682926829^(1/20) or that^0.05 = 1.0179316092382140458823473304434

Scientific calculators go down to the last decimal... No need to post this question because this website has a literal calculator :O

Yes there definitely is a good strategy. We have 10 different variables.

Case 1, the sum is = 0:

There is 1 solution, where all variables are equal to 0.

Case 2, the sum is = 1:

There are 10 choose 1 ways to arrange the value of 1 among the 10 variables, so there are 10 solutions.

Case 3, the sum is = 2.

We can have 10 ways to arrange the 2. But if we have two 1s, we have (10 choose 2) ways to do it = 45.

Total sum is 10 + 45 + 10 + 1 = 66 total cases.

Guest, please stop posting random answers. 

We know PQ is 18, and by pythagorean theorem, we can conclude that RS (the points of tangency of circles P and Q respectively) has length sqrt(18^2 - 2^2). sqrt(320) simplifies to 8sqrt(5). (unnessecary but you can do it this way)

Let QR = x. By similar triangles, x/8 = (x + PQ)/10

10x = 8x + 8*18

2x = 144

x = 72 = QR

There is no diagram below, please repost your question with "the diagram below" please, thank you.

8x^3 = sqrt(128) = 8sqrt(2)

x^3 = sqrt(2) = (2)^0.5

So x = (2)^(1/2)(1/3). Thus, n = 6.

BDI is not a triangle by the triangle inequality, please talk to your teacher/problem owner to tell them of this error/typo.

Remember: (You can simplify by expanding out)

a^3 + b^3 = (a + b)(a^2 - ab + b^2)

and

a^2 + b^2 = (a + b)^2 - 2ab

Substituting in, you get:

(a + b)(a^2 - ab + b^2) = 812 + (a + b)^2 - 2ab

14[(a + b)^2 - 2ab - ab] = 812 + 196 - 2ab

14(196 - 3ab) = 1008 - 2ab 

2744 - 42ab = 1008 - 2ab

1736 = 40ab

ab = 43.4

a + b = 14

Write a quadratic equation using vieta's formula:

x^2 - 14x + 43.4 = 0. x is the values of a and b.

a and b are 14 +- sqrt(22.4)) / 2

They have a common denominator so you can multiply both sides by a^3 + 7.

You obtain the equation 1 = -a^3, a = -1

Combine like terms, so combine the ones with the same variable or the ones with the same constant/normal numbers and you get:

5c + d + 1