(1/49)^(4m - 2) = 7^(- 10m - 2)
(4m-2) Log (1/49) = (- 10m - 2 ) Log 7
(4m - 2)(- 1.6902) = (- 10m - 2)(0.8451)
- 6.7608m + 3.3804 = - 8.451m - 1.6902
- 6.7608m + 8.451m = - 1.6902 - 3.3804
1.6902m = - 5.0706
m = - 11.8314 / 1.6902
m = - 3
Link:https://ph.answers.yahoo.com/question/index?qid=20180123030240AASHvba
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