If there isn't one, of course.
I don't know... We should suggest that to Mr. Massow!
\({7 \over8}+{3 \over5}=x\)
LCM
\({35 \over40}+{24 \over40}=x\)
Add the NUMERATORS ONLY
\(x={54 \over40}\)
Simplify
\(x=1{14\over40}\)
\(x = 1{7\over20}\)
Whoops! That's right! CPhill is correct. I misread the question. :P
There's a calculator, y'know. Use it for these problems.
244/0.4 = 610
The equation you have is 2x+90.
2(150)+90=300+90=390.
It will cost the school $390 to print 150 buttons.
Divide 751 by 1413.
751/1413 = 0.5314932767162067
So, 751 is 53.14932767162067% of 1413.
No, 2+0=2. You add nothing, so it stays the same.
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