Sasini

It's ok dr

3 +13(-11d + 10)

3 -143d + 130

133 -143d

I think it is the answer

I can't understand the quesion. sry

Good Luck dr

-7(a^2)(-b^3)

$${\mathtt{\,-\,}}\left({\mathtt{7}}{\mathtt{\,\times\,}}\left({{\mathtt{a}}}^{{\mathtt{2}}}{\mathtt{\,\times\,}}\left({\mathtt{\,-\,}}\left({{\mathtt{b}}}^{{\mathtt{3}}}\right)\right)\right)\right)$$

-7*$${\mathtt{\,-\,}}\left({{\mathtt{a}}}^{{\mathtt{2}}}{\mathtt{\,\times\,}}{{\mathtt{b}}}^{{\mathtt{3}}}\right)$$

-7-(a^2-b^3)

-7a^2b^3 This is the finally anwser

six =6

seven =7

So that 6 + 7 is 13,

I think that's a simply question.

-3(7+4) -2(7-9) = 48+7 -84

First we  sove the left hand side.

It is:

L.H.S- -3(7+4) -2(7-9)

        =-3*11  -2*(-2)

        =-33 +4

        = -29

Then we solve the right hand side.

It is:

R.H.S- 48+7-84

        = 55 - 84

        = -29

So that: L.H.S = R.H.S

3x+1 =21

3x     =21-1

3x     =20

x       =$${\frac{{\mathtt{20}}}{{\mathtt{3}}}}$$ = 6.66....

So that value of the x is 6.66

4.83% is a presentage

Now we can write it  ; $${\frac{{\mathtt{4.83}}}{{\mathtt{100}}}}$$

Then we can slove this problem simply

It is; $${\frac{{\mathtt{4.83}}}{{\mathtt{100}}}}{\mathtt{\,\times\,}}{\mathtt{283\,000}}$$ =$${\mathtt{4.83}}{\mathtt{\,\times\,}}{\mathtt{2\,830}}$$ = $${\mathtt{13\,668.9}}$$

finaly answer is 13668.9

log (x+2)=log (3x-3)

(x+2)=(3x-3)

3x-3 = x+2

3x -x= 2 +3

2x    = 5

 x     =5/2

        =2.5

2.5 is the value to x