$${\frac{{\mathtt{125}}}{\left({\frac{{\mathtt{5}}}{{\mathtt{6}}}}\right)}}{\mathtt{\,\times\,}}\left({\mathtt{15}}{\mathtt{\,-\,}}{\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{3}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{3}}}{{\mathtt{4}}}}\right){\mathtt{\,\times\,}}{\mathtt{2}} = {\mathtt{2\,925}}$$alright i did it is this better?