Suppose that a2 varies inversely with b3. If a=7when b=3, find the value of a2 when b=6.
a2 = k / b3
72 = k / 33
49 = k / 27 ⇒ k = 49 / 27
When b = 6
a2 = 49 / (27*63 )
a2 = 49 / 5832
+4624 
