If 2/3*3/4*4/5* ... * n/(n+1) = 1/500, what is the sum of the numerator and denominator of the largest fraction on the left side of the equation?
Note that everything cancels out so that the final equation is 2/(n+1).
2/(n+1) = 1/500
Can you take it from here?
=^._.^=
