Find the product of all positive integer values of \(c\) such that \(8x^2+15x+c=0\) has two real roots.
THANKS FOR ALL HHELP
8x^2 + 15x + c = 0
To have two real roots, the discriminant must be > 0
So
15^2 - 4*8*c > 0
225 > 32c
c < 225/32
c< floor [ 225/32]
c < 7 but also > 0 since c must be positive
So....the product of all positve c's = 7! = 5040
+88 
