what is the answer to 4x^2-24x+32=0

$$\\4x^2-24x+32=0\\ $first simplify by dividing both sides by 4$\\ x^2-6x+8=0\\ $You need 2 numbers that mult to +8 and add to -6$\\ $ These numbers will be -4 and -2$\\ (x-4)(x-2)=0\\ x=4 \;or \;x=2$$

$${\mathtt{4}}{\mathtt{\,\times\,}}{{\mathtt{x}}}^{{\mathtt{2}}}{\mathtt{\,-\,}}{\mathtt{24}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{32}} = {\mathtt{0}} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = {\mathtt{4}}\\ {\mathtt{x}} = {\mathtt{2}}\\ \end{array} \right\}$$