25 tangent (9+33) - 25 tanget (33) =_______________ cm
Rectangle area of 40 has base = x and height = 1/2 x
x * 1/2 x = 40
x = sqrt 80 triangle has height = 1/2 *sqrt 80 and base sqrt 80 area = 1/2 base * height = 20 units2
info missing in the Q posting.......
65-25 = 40 inches left for the two sides
tringle side length rule
means 8 and 32 side lengths
Right triqangle hypotenuse = 80 m/s * 120 seconds = 9600 m
sin 60 = opposite side / hypotenuse
sqrt 3/ 2 = altitude / 9600
9600 * sqrt (3) / 2 = altitude = 8313. 8 m
Line equation y = -2x + b y = 0 when x = - 5 sub these into the equation to calc b
0 = (-2)(-5) + b so b = -10
y = -2x -10 y intercept = b = -10
Find side BD via Pythag theorem to be sqrt 8
tan B = opp side / adj side = 3 / sqrt 8
h = 0 when the ball hits the surface, sooooo
0 = -6t^2 -5t+56 use quadratic formula a = -6 b = -5 c = 56
to find t = 2.67 sec or t = - 3.5 (throw out)
Center , h, k = (0,-8)
(x-0)^2 + (y+8)^2 = r^2 radus is distance from center to the other point given use distance formula
d^2 =r^2= 2^2 +13^2 = 173
x^2 + (y+8)^2 = 173
